zoj 3406 Another Very Easy Task

This task is so easy that the description is omitted.

#include <iostream>
#include <cctype>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;
char a[100000];
int main(void){
#ifndef ONLINE_JUDGE
  freopen("1.in", "r", stdin);
  freopen("1.out", "w", stdout);
#endif
  while (gets(a)){
    int len = strlen(a); bool flag = false; int cnt = 0;
    for (int i = 0; i < len; ++i){
      cnt = 0; flag = false;
      while (isalpha(a[i])){
        if (!flag){
          flag = true; 
          printf("%c", a[i]);
        }
        else cnt++; 
        i++;
      }
      if (cnt == 1) printf("%c", a[i-1]);
      else if (cnt >= 2){printf("%d", cnt-1); printf("%c", a[i-1]);}
      if (i < len) printf("%c", a[i]);
    }
    printf("\n");
  }
  return 0;
}

这道水题，纠结好久，唉，真是思维不严谨啊，以后输出字符类的输出的题目一定要输出到文件，不然哪里错了都看不出来，水题还这么卡，看来自己需要练练手速，还有做题的准确度。